![]() ![]() This is because there was more mass of water than steel and because water has such high specific heat. In this case, the temperature of the steel dropped significantly and the temperature of the water rose slightly. 466*10*( 90 – T final )Ĩ3.68* T final – 836.8 = 419.4 – 4.66 * T finalįinally, we re-arrange the equation above, and solve for the final temperature: Next, we enter the values provided above:Ģ0*4.184*( T final – 10 ) =. M water*C water*(T final-T water)=m steel*C steel*(T steel-T final) The mass of the steel is 10g and the mass of the water is 20g.466 J/gC and the specific heat of water is 4.184 J/gC. The initial temperature of the steel is 90C and the initial temperature of the water is 10C.Let’s take a look at a sample problem of how to calculate the final temperature of two combined objects.įor this example, we are going to say we have a hot steel ball that’s dropped into a cooler body of water. Where TF is the final temperature Final Temperature Example Problem Where q1 and q2 are the heat of both objects after combination. ![]() The following formula is used to calculate the final temperature when combining two substances of different heats.
0 Comments
Leave a Reply. |
Details
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |